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Howdie all,
I'm soo glad I found this forum, people are genuinely working together instead of ignoring their fellow physics brethren =)
A pair of square parallel conducting plates, having sides of length .05 meter, are .01 meter apart and are connected to a 200 volt power supply. An electron is moving horizontally with a speed of 3 x 10^7 m/s when it enters the region between the plates. Neglect gravitation and the distortion of the electric field around the edges of the plates.

+

200 V > e 3 x 10^7 m/s



Side length is .05 m
1. Determine the magnitude of the electric field in the region between the plates and indicate its direction on the figure above.
E=V/d
E=200/.1
E=2000, down

+ !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
200 V > e 3 x 10^7 m/s!!!!!!
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
 vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv (down arrows)

2. Determine the magnitude and direction of the acceleration of the electron in the region between the plates.
E=F/q F=ma
Eq=F
2000 x 1.60 x 10^19=ma
a=3.513 x 10^14 m/s^2, up
3. Determine the magnitude of the vertical displacement of the elctron for the time interval during which it moves through the region between the plates.
d=vt
.05=3 x 10^7 x t
t=1.67 x 10^9
d=vt +(1/2)a x t^2
d=.0505 m
4.On the diagram below, sketch the path of the electron as it moves through and after it emerges from the region between the plates. The dash lines in the diagramhave been added for reference only.
/////
.005/////////////////////////////////////////////////////////
/////////////////////////////
(median line)
.005

(The line is curving slowly, then faster upward)
5. A magnetic field could be placed in the region between the plates which would cause the electron to continue to travel horizontally in a straight line through the region between the plates. Determine both the magnitude and the direction of this magnetic field.
This is really the one I don't know how to do. I realize that the vertical force must be zero between the magnetic and the electrical force, but I don't know how to do it mathematically.
Thanks, again, for your help =)
I'm soo glad I found this forum, people are genuinely working together instead of ignoring their fellow physics brethren =)
A pair of square parallel conducting plates, having sides of length .05 meter, are .01 meter apart and are connected to a 200 volt power supply. An electron is moving horizontally with a speed of 3 x 10^7 m/s when it enters the region between the plates. Neglect gravitation and the distortion of the electric field around the edges of the plates.

+

200 V > e 3 x 10^7 m/s



Side length is .05 m
1. Determine the magnitude of the electric field in the region between the plates and indicate its direction on the figure above.
E=V/d
E=200/.1
E=2000, down

+ !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
200 V > e 3 x 10^7 m/s!!!!!!
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
 vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv (down arrows)

2. Determine the magnitude and direction of the acceleration of the electron in the region between the plates.
E=F/q F=ma
Eq=F
2000 x 1.60 x 10^19=ma
a=3.513 x 10^14 m/s^2, up
3. Determine the magnitude of the vertical displacement of the elctron for the time interval during which it moves through the region between the plates.
d=vt
.05=3 x 10^7 x t
t=1.67 x 10^9
d=vt +(1/2)a x t^2
d=.0505 m
4.On the diagram below, sketch the path of the electron as it moves through and after it emerges from the region between the plates. The dash lines in the diagramhave been added for reference only.
/////
.005/////////////////////////////////////////////////////////
/////////////////////////////
(median line)
.005

(The line is curving slowly, then faster upward)
5. A magnetic field could be placed in the region between the plates which would cause the electron to continue to travel horizontally in a straight line through the region between the plates. Determine both the magnitude and the direction of this magnetic field.
This is really the one I don't know how to do. I realize that the vertical force must be zero between the magnetic and the electrical force, but I don't know how to do it mathematically.
Thanks, again, for your help =)