- #1

- 33

- 0

Split from: https://www.physicsforums.com/threads/acceleration-and-the-twin-paradox.779110/

I find the discussion about acceleration confusing. I want to avoid that.

So try this scenario: Lucy is traveling at .6c relative to Bob. Just when they reach their point of closest approach, one kilometer, they synchronize clocks.

As their distance increases, each of them sees a red shift. Each estimates the other's time is dilated by a factor of gamma, that is 1/sqrt(1-.6^2)=1/sqrt(.64)=1/.8

After some distance, Lucy meets Betsy who is traveling the opposite direction at .6c relative to Bob. When they reach their point of closest approach, one kilometer, Lucy gives Betsy her clock's current time and Betsy sets her clock by it. Betsy and Bob will both see each other's light is blue-shifted. They both calculate the other's time is dilated by a factor of gamma = 1/.8.

When Betsy and Bob reach their point of closest approach, one kilometer, they exchange times. Which clock will be ahead, and by how much?

So try this scenario: Lucy is traveling at .6c relative to Bob. Just when they reach their point of closest approach, one kilometer, they synchronize clocks.

As their distance increases, each of them sees a red shift. Each estimates the other's time is dilated by a factor of gamma, that is 1/sqrt(1-.6^2)=1/sqrt(.64)=1/.8

After some distance, Lucy meets Betsy who is traveling the opposite direction at .6c relative to Bob. When they reach their point of closest approach, one kilometer, Lucy gives Betsy her clock's current time and Betsy sets her clock by it. Betsy and Bob will both see each other's light is blue-shifted. They both calculate the other's time is dilated by a factor of gamma = 1/.8.

When Betsy and Bob reach their point of closest approach, one kilometer, they exchange times. Which clock will be ahead, and by how much?