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df/dt =iR

df/dt = dq/dt R

df =dq R

but if we take into consideration the self inductance of the loop then the process goes as follows

we know that

flux due to current in circuit(f1) =L i

where L is the self inductance of the loop

we can then say

df1/dt = Ldi/dt

now writing the equation of the ptentials of the loop

if f2 is the flux due to the external fieldthen

df2/dt-Ldi/dt=iR

df2/dt-df1/dt= dq/dt R

df2-df1=dqR

thus we conclude that change in flux due to external field - change in flux due to current in loop=charge flown divided by resistance

but when i tried to verify this using a simple problem

my answer didnt agree with the result derived

please verify it