Based on the following chart, what ions would you use to construct an electrochemical cell with potential closest to 2.00 V?
I know that I am supposed to add the voltages of the 2 reactions but I am not sure how the signs would go. We are not using a textbook for this class so I have nothing to reference.
The Attempt at a Solution
I'd use the following reactions and voltages
Fe3+ -> Fe2+ (-0.771 gaining electron)
Na (s) -> Na+ (+2.71 losing electron)
so the cell voltage would be 1.94V. Is this correct?
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