1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

ElectroChemistry PH Question

  1. Jul 27, 2011 #1
    1. The problem statement, all variables and given/known data
    A current of 10.7 Amps is applied to a 1.30 L solution of 0.550M HBr converting some of the H+ to H2(g), which bubbles out of solution. What is the PH of the solution after 77 minutes.


    2. Relevant equations



    3. The attempt at a solution
    (10.7 C/s)(1 mol e/96485 C)(2 mol H+/2 mol e)(60s/min)(77 min) = .512 mol H+

    .512 mol H+/1.30L = .394M H+
    -log(.394M) = .405 = PH

    This was incorrect
     
  2. jcsd
  3. Jul 27, 2011 #2
    You started with a certain amount of H+ in the solution. The electrolysis removed some. Now you need to calculate what's left.
     
  4. Jul 27, 2011 #3
    I see will try, thank you
     
  5. Jul 27, 2011 #4
    It worked, thank you
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: ElectroChemistry PH Question
Loading...