(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A current of 10.7 Amps is applied to a 1.30 L solution of 0.550M HBr converting some of the H+ to H2(g), which bubbles out of solution. What is the PH of the solution after 77 minutes.

2. Relevant equations

3. The attempt at a solution

(10.7 C/s)(1 mol e/96485 C)(2 mol H+/2 mol e)(60s/min)(77 min) = .512 mol H+

.512 mol H+/1.30L = .394M H+

-log(.394M) = .405 = PH

This was incorrect

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# Homework Help: ElectroChemistry PH Question

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