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Electrochemistry (solubility)

  1. Feb 4, 2006 #1
    hey i seem to be having a lot of trouble qith this question may i get some help?
    The standard potential of the cell below is + 0.9509 V at 25 oC. Calculate the solubility, normally called s, of AgI (Note: Enter the natural log of s (ln s) as your answer)

    Ag|AgI(s)|AgI(aq)|Ag

    i'm using nernst equation and found the standard potential for Ag+,Ag to be 0.7991V

    i am using Eo as 0.7991 and E as 0.9509 and rearanging the equation to find the solubility as LnS.. the correct answer is suppose to be -18.51.. where i am going wrong? please help.
    thanks

    n.b standard reduction potential of AgI(s) is -.15V
     
    Last edited: Feb 4, 2006
  2. jcsd
  3. Feb 7, 2006 #2

    Borek

    User Avatar

    Staff: Mentor

    IIRC -18.51 is not a natural log of the AgI solubility product - it's decimal log.
     
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