hey i seem to be having a lot of trouble qith this question may i get some help?(adsbygoogle = window.adsbygoogle || []).push({});

The standard potential of the cell below is + 0.9509 V at 25 oC. Calculate the solubility, normally called s, of AgI (Note: Enter the natural log of s (ln s) as your answer)

Ag|AgI(s)|AgI(aq)|Ag

i'm using nernst equation and found the standard potential for Ag+,Ag to be 0.7991V

i am using Eo as 0.7991 and E as 0.9509 and rearanging the equation to find the solubility as LnS.. the correct answer is suppose to be -18.51.. where i am going wrong? please help.

thanks

n.b standard reduction potential of AgI(s) is -.15V

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# Homework Help: Electrochemistry (solubility)

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