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## Homework Statement

A pump is electrogenic, meaning that 3 Na ions are pumped in for 2 K ions that pumps out. Given that the active current --> I' (Na) 30 E-9 , find the passive current of Na --> I (Na). Assume cell is in steady state so Vm, [Na] inside and [K] inside is constant.

## Homework Equations

passive current Na/passive current K = active current Na/ active current of K = 3/2

Is it possible to find a value for passive Na current if I don't know the passive current of K?

I' (Na) / I' (K) = 3/2

30 E-9 / I' (K) = 3/2

I' (K) =2 E-8 , so this is the active current of K+ ion. I don't get how I can use this to find the passive current of Na