# Electrogenic membrane pump

• higherme

## Homework Statement

A pump is electrogenic, meaning that 3 Na ions are pumped in for 2 K ions that pumps out. Given that the active current --> I' (Na) 30 E-9 , find the passive current of Na --> I (Na). Assume cell is in steady state so Vm, [Na] inside and [K] inside is constant.

## Homework Equations

passive current Na/passive current K = active current Na/ active current of K = 3/2

Is it possible to find a value for passive Na current if I don't know the passive current of K?

I' (Na) / I' (K) = 3/2
30 E-9 / I' (K) = 3/2
I' (K) =2 E-8 , so this is the active current of K+ ion. I don't get how I can use this to find the passive current of Na

actually, would this be right

the passive current of Na is the same as the active current of Na... same magnitude, but different direction. So since give active current is +30E-9... then I don't even need any equations to find the passive current of Na because it's simply the same but negative --> - 30E-9

is this correct ?