(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An electron beam with negligible velocity in the x direction is emitted from a heated plane cathode through a vacuum towards a plane anode at x = s, there the potential is V = Vo. At the cathode V(x) = 0 and x = 0. The charge density of the beam is;

p = - (4eoVo)/(9s^(4/3)x^2/3

Show that V(x) takes the form V(x) = Vos^p.x^q

2. Relevant equations

3. The attempt at a solution

I have worked out that I have to use: divE= p/e0

So when I substitute the expression I have for p into this I ger:

divE= (4Vo)/(9s^(4/3)x^2/3

However I do not know how to get this into a form to find V(x), im stuck. Would appretiate some helpful hints or even something a bit more forceful. Thanks

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# Homework Help: Electromag Question?

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