Electromagnetic Fields due to Accelerating Charge

In summary, an electromagnetic field is a physical field generated by electrically charged particles that includes both an electric and magnetic field. It is created by accelerating charges, such as electrons, and can produce various forms of electromagnetic radiation. The effects of electromagnetic fields on living organisms are still being studied, and to protect ourselves, we can limit exposure and increase distance from sources.
  • #1
Yoni V
44
0

Homework Statement


What are the electric and magnetic fields due to a charge that is moving with uniform acceleration?
(Non relativistic)

Homework Equations


Retarded solutions for the vector and scalar potentials.

The Attempt at a Solution


My attempt might be an overkill because I'm using the integral solution
$$
\psi\left(\boldsymbol{r},t\right)=\int_{V}\frac{\left[f\left(\boldsymbol{r}',t\right)\right]_{ret}}{\left|\boldsymbol{r}-\boldsymbol{r}'\right|}d^{3}r'
$$
for the potential as an exercise for correct use of this formula. Perhaps since it's a single particle I can solve for, say, the scalar potential directly from Coulomb's law and just retard the solution. But I'm not sure this is a valid approach because the law essentially assumes electrostatics and immediate information flow without considering the propagation of information through the wave equation (although retarding the solution might just give it the required fix. If anyone can clarify this I'll be grateful). But more importantly, using the above formula I get really mixed up about which of the term is which, and specifically which gets retarded, so I want to be sure I can handle this equation properly for future problems as well.
So I proceed as follows for the scalar potential:

The charge distribution is given by (for simplicity assuming everything is on the x axis):
$$
\rho\left(\boldsymbol{r},t\right)=q\delta\left(y\right)\delta\left(z\right)\delta\left(x-\frac{1}{2}at^{2}\right)
$$
yielding
$$
\phi\left(\boldsymbol{r},t\right)=\int\frac{q\delta\left(y'\right)\delta\left(z'\right)\delta\left(x'-\frac{1}{2}at'^{2}\right)}{\left|\boldsymbol{r}-\boldsymbol{r}'\right|}\delta\left(t'-\left(t-\frac{\left|\boldsymbol{r}-\frac{1}{2}at^{2}\hat{x}\right|}{c}\right)\right)dt'd^{3}r'
\\
=\int\frac{q\delta\left(y'\right)\delta\left(z'\right)\delta\left(x'-\frac{1}{2}a\left(t-\frac{\left|\boldsymbol{r}-\frac{1}{2}at^{2}\hat{x}\right|}{c}\right)^{2}\right)}{\left|\boldsymbol{r}-\boldsymbol{r}'\right|}d^{3}r'
\\
=\frac{q}{\left|\boldsymbol{r}-\frac{1}{2}a\left(t-\frac{\left|\boldsymbol{r}-\frac{1}{2}at^{2}\hat{x}\right|}{c}\right)^{2}\hat{x}\right|}
$$

As can be seen, it really does turn out (at least in this case) just a retardation to the simple solution, but I'm still not sure that I handled the tagging of the variables and retarding them properly.

Is this a correct result? And at which conditions if any may I directly use electrostatics laws such as Coulomb's and retard them in a straightforward fashion? Thanks.
 
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  • #2


Your approach seems correct, although it may be a bit overcomplicated for this particular problem. In general, the electric and magnetic fields due to a charge moving with uniform acceleration can be found using the Lienard-Wiechert potentials, which are the retarded solutions for the vector and scalar potentials. These potentials take into account the propagation of information through the wave equation, and are valid for non-relativistic as well as relativistic speeds.

To answer your question about when you can use electrostatics laws and simply retard them, it depends on the specific problem. In general, if the source of the electric and magnetic fields is moving with a constant velocity, you can use the retarded solutions for the potentials. However, if the source is accelerating, as in this case, you will need to use the Lienard-Wiechert potentials to properly account for the time delay in the propagation of information.

In summary, your approach is correct, but it may be simpler to use the Lienard-Wiechert potentials directly instead of using the integral solution. Additionally, for future problems involving charges moving with uniform acceleration, you should use the Lienard-Wiechert potentials to properly account for the time delay in the propagation of information.
 

1. What is an electromagnetic field?

An electromagnetic field is a physical field generated by electrically charged particles that exerts force on other electrically charged particles within the field. It consists of both an electric field and a magnetic field, and together they can transport energy and information through space.

2. How is an electromagnetic field created by accelerating charge?

According to Maxwell's equations, a changing electric field creates a magnetic field, and a changing magnetic field creates an electric field. When electrically charged particles are accelerated, their velocity changes, resulting in a changing electric field and subsequently a changing magnetic field, creating an electromagnetic field.

3. What are some examples of electromagnetic fields due to accelerating charge?

Some examples of electromagnetic fields due to accelerating charge include radio waves, microwaves, visible light, X-rays, and gamma rays. These are all forms of electromagnetic radiation, which is produced by accelerating charged particles, such as electrons.

4. What are the effects of electromagnetic fields on living organisms?

The effects of electromagnetic fields on living organisms are still being studied and debated. Some studies have shown that exposure to high levels of electromagnetic radiation can cause harm to living cells and tissues, while others have not found any significant health effects. More research is needed to fully understand the potential impacts of electromagnetic fields on living organisms.

5. How can we protect ourselves from electromagnetic fields?

To protect ourselves from electromagnetic fields, we can limit our exposure to sources of electromagnetic radiation, such as cell phones, Wi-Fi routers, and power lines. We can also use shielding materials, such as metal, to block or reduce the strength of electromagnetic fields. However, it is important to note that the strength of an electromagnetic field decreases with distance, so simply increasing the distance from the source can also be an effective way to reduce exposure.

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