Electromagnetic Induction and Faraday's Law

  • Thread starter airkapp
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  • #1
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The generator of a car idling at 950 rpm produces 12.4 V. What will the output be at a rotation speed of 2500 rpm assuming nothing else changes?

I'm guessing that is easier and I'm looking to make it harder. I can't find anything in my textbook involving rpm. I'm thinkin to use this formula
E = NBAw but I'm actually not quit sure how to approach the problem.

is N my rpm? and then I do an initial rpm and final rpm sequence?
 

Answers and Replies

  • #2
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N is number of loop... [tex] \omega [/tex] is the angular velocity.....

the rpm (rotation per minute, or radian per minute) is directly proportional to the angular velocity.... does that make sense to you?
 
  • #3
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vincentchan said:
N is number of loop... [tex] \omega [/tex] is the angular velocity.....

the rpm (rotation per minute, or radian per minute) is directly proportional to the angular velocity.... does that make sense to you?

so i could set this up as a proportion?

950/12.4 V =2500/x Volts ?

thanks.
 
  • #4
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I think you should also consider the back EMF.
 
  • #5
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ramollari said:
I think you should also consider the back EMF.
sorry, I'm not following. If all things remain constant why would I consider that? The back emf oppose the motion (Lenz's law) correct, but if everything remains constant... :confused:
 

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