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Electromagnetic Induction in the Earths Field

  • Thread starter pobatso
  • Start date
17
0
Hi all, brand new to these forums but help you can give me some guidance with some summer exam revision!
Heres a fairly simple one I can't see through for some reason, using EMF = B.u.l etc:

1. A copper disc, 250mm in diameter, is reotated at 300 rpm about a horizontal axis through its centre and perpendicular to its plane. If the axis points magnetic north and south, calculate the emf between the circumference of the disc and the axis. Assume the horizontal comp. of the earths mag field to be 18 uT



2. EMF = B.u.L



3. B = Stated, u = speed of the circumference of the ring, so (pi x D)(revs. per sec), L = Circumference (0.7854m) Ans= 5.6x10^-5, wrong answer :(

Im pretty sure its simple, but I think Im confusing some of the figures. Cheers!
 

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