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Electromagnetic physics

  1. Apr 4, 2007 #1
    1. The problem statement, all variables and given/known data

    2 identical +10uC point charges are initially spaced 5.5cm from each other. If they are released at the same instant from rest, how fast will they be moving when they are very far away from each other? Assume they have identical masses of 1.0mg.

    2. Relevant equations

    Maybe... W=Fd=qEd=qV=0.5mv^2

    3. The attempt at a solution

    initially,
    W=qEd
    =kqQ/r
    =8.99*10^9*(10*10^-6)*(10*10^-6)/0.055
    =16.3454

    when they are very far apart,
    W=0.5mv^2
    =0.5*10^-6*v^2
    =16.3454

    v=(16.3454*2/10^-6)^0.5
    =5717ms^-1

    but the real answer is 4.1*10^3ms^-1...
     
  2. jcsd
  3. Apr 4, 2007 #2

    marcusl

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    Since both charges are released, each carries W/2 kinetic energy at a large distance. Dividing your result by sqrt(2) gives the correct speed.
     
  4. Apr 4, 2007 #3
    But how do you know that each charges only carries W/2 KE?
    I don't quite understand that....
     
  5. Apr 4, 2007 #4

    marcusl

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    Your problem states that both charges are released simultaneously. They fly apart from each other, and since they are identical, newton's laws enforce that they will move equally. The total potential energy W that you calculated therefore divides evenly between them.
     
  6. Apr 4, 2007 #5
    Oh, I got it!
    So if the charges are, for example +10uC and +20uC, then the velocity of charge (+10uC) would be v=(W/3*2/10^-6)^0.5, right?
     
  7. Apr 4, 2007 #6

    marcusl

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    No, the speeds differ only if the masses differ. The force each feels is the same regardless of charge because every action has an equal and opposite reaction (remember that one?) but the lighter particle will accelerate more (F=ma).
     
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