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HF(A)=EF(A) what is easier...then why use renormaliztion and all that?..in electromagnetism can the Hamiltonian description presented above describe quantum electormagnetism?..then why qed?..

- Thread starter eljose79
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- #1

- 214

- 1

HF(A)=EF(A) what is easier...then why use renormaliztion and all that?..in electromagnetism can the Hamiltonian description presented above describe quantum electormagnetism?..then why qed?..

- #2

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Hi eljose79Originally posted by eljose79

HF(A)=EF(A) what is easier...then why use renormaliztion and all that?..in electromagnetism can the Hamiltonian description presented above describe quantum electormagnetism?..then why qed?..

Because "this way" explains nothing. Just try to calculate the anomalous magnetic moment of electron by "this way"... of course you can't...

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