1. A 35 loop square coil 0.12 m on a side is positioned in a 0.050 T magnetic field. A 0.20 kg mass is suspended from one side of the coil as shown in the diagram attached. How much current must pass through the coil in order for the coil to remain horizontal? A. 2.3 A B. 4.7 A C. 9.3 A D. 330 A 2. Relevant equations τ=BAIN F=IlB 3. The attempt at a solution τ=BAIN so I=τ/BAN I know that BAN is 0.050 x 0.122 x 35 (the information is given). However, I'm having a little trouble finding τ (torque). I know that I need to find the forces on the square coil. But since I don't know I (current), I won't be able to find the force with the equation. Any help would be greatly appreciated.