# Electromagnetism Question

• ryanwilk
In summary, the total force on a wire segment carrying a current of 1.8A from point a to point b in a uniform magnetic field of 1.2T acting in the z-direction is 0.0864i - 0.0648j. This is equal to the force on a straight wire segment from a to b. The right-hand rule and the formula F=BIL were used to determine the direction and magnitude of each force.

#### ryanwilk

1. "A wire segment carries a current of 1.8A from a to b. There is a uniform magnetic field of 1.2T acting in the z-direction. Find the total force on the wire and show that the total force is the same as if the wire were a straight segment from a to b".

I've attached the diagram showing what the segment looks like and I've called the point between a and b, c.

2. Homework Equations : F=BIL

3. Would this be right?:
Fac = ILBcos90 = 0N (90° since the x-direction is orthogonal to z)
Fcb = ILBsin90 = ILB = 1.8 x 0.04 x 1.2 = 0.0864N (90° since the y-direction is orthogonal to z)
=> Facb = 0.0864N

Fab = ILBsinθ = ILBsin(arctan(4/3)) = 0.8ILB = 0.8 x 1.8 x 0.05 x 1.2 = 0.0864N

Therefore, Facb = Fab

Or is it just a coincidence that the two values come out to be the same? Because I don't really understand why it would be cos90 from a to c and sin90 from c to b =s

#### Attachments

• wire segment.bmp
142.5 KB · Views: 468
Welcome to PF

There are some problems with your derivation. For one, all currents (ac, cb, and ab) are perpendicular to the magnetic field. So use F=BIL to find each force, with no cos or sin factors. None of the three forces will be zero.

You'll also need to use the right-hand rule to figure out the direction of each force, and combine the ac & cb forces.

So, would this be right:
Fac = ILB = 0.0648N in the -ve y-direction so -0.0648j
Fcb = ILB = 0.0864N in the +ve x-direction so 0.0864i
=> Facb = 0.0864i - 0.0648j

Fab = ILB = 0.108N
The direction is sin(arctan(4/3))Fi - cos(arctan(4/3))Fj
= 0.0864i - 0.0648j

Not sure about the signs though because the right-hand rule really confuses me =s

Last edited:
Looks good! The signs are correct too.

Oh good
Thanks a lot.

## 1) What is electromagnetism?

Electromagnetism is a fundamental force of nature that describes the interaction between electrically charged particles. It is responsible for phenomena such as electricity, magnetism, and light.

## 2) How do electromagnets work?

Electromagnets work by using an electric current to create a magnetic field. When the current flows through a wire, it generates a magnetic field around the wire. By coiling the wire, the magnetic field is amplified, creating a strong electromagnet.

## 3) What are the applications of electromagnetism?

Electromagnetism has a wide range of applications in our daily lives. Some examples include electric motors, generators, telecommunication systems, MRI machines, and various electronic devices.

## 4) What is the relationship between electricity and magnetism?

Electricity and magnetism are closely related and are actually two different aspects of the same force, electromagnetism. An electric current creates a magnetic field, and a changing magnetic field can induce an electric current.

## 5) How does electromagnetism relate to light?

Light is an electromagnetic wave, which means it is a combination of electric and magnetic fields oscillating in a perpendicular direction. This connection between electricity and magnetism allows us to use electromagnetism to produce and detect light in various forms, including radio waves, microwaves, and visible light.