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Electromatnetism question

  1. Feb 3, 2005 #1


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    A dipole is formed by placing a positive charge of 10 nC at z=0.5micrometers and a negative charge of -10 nC at z= -0.5 micrometers. Determine the potential and the electric field intensity at a point P(0,0,1).

    I'm using the equation for potential (V=q/4*pi*epsillon*R) and for electric field intensity (E=q/4*pi*epsillon*R^2) but my problem is that I don't know how to treat the two charges. Do I calculate the potential and electric field intensity at point P due to each charge and then add them or is there another way of approaching the question?

    Any help would be greatly appreciated.
  2. jcsd
  3. Feb 3, 2005 #2
    yep,,, that's how its done... both E and V follow the superposition principle which allows you calculate for each charge and add to get the total result. for E, make sure you treat them as vectors though
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