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Electron and magnetic fields

  1. Aug 1, 2007 #1
    Question solved!
    Last edited: Aug 1, 2007
  2. jcsd
  3. Aug 1, 2007 #2


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    The current refers to the conventional current, opposite to the direction of motion of electrons in the wire, i.e., all electrons in the description moves in the same direction. Treat this as you do two parallel wires with current in them, then.
  4. Aug 1, 2007 #3
    If I find out B of the wire, can I sub the q/v/sin theta of the electron into Fm = qvbsin theta to get the Fm then?
  5. Aug 1, 2007 #4
    Yes, you can. ;)
  6. Aug 1, 2007 #5
    Beautiful. Thanks guys!:rofl:
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