Electron Configuration of Platinum

  1. 1. The problem statement, all variables and given/known data
    Why is the electron configuration of neutral Platinum:

    [itex]Pt = [Xe]4f ^{14} 5d ^{9} 6s ^{1}[/itex]

    and not?:

    [itex]Pt = [Xe]4f ^{14} 5d ^{10} 6s ^{0}[/itex]

    I thought that if the two electrons from the 6s sub-shell were to move to the 5d sub-shell, then 5d sub-shell would be fully paired, hence stability? However, this is not the case as the actual configuration calls for only one electron to be moved from the 6s sub-shell, rather than two. Can someone explain to me why this is the case?
     
  2. jcsd
Know someone interested in this topic? Share this thead via email, Google+, Twitter, or Facebook

Have something to add?

0
Draft saved Draft deleted
Similar discussions for: Electron Configuration of Platinum
Loading...