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Electron in a B field.

  1. Mar 25, 2013 #1
    Lets say I have a spin-1/2 particle that is about to enter a non-constant B field.
    the spin 1/2 particle has a state vector of
    [itex] |\psi>= \frac{|+z>}{\sqrt{2}} + \frac{|-z>}{\sqrt{2}}[/itex]
    What if the B field was also in a superposition like
    [itex] |\psi>= \frac{ \sqrt{2}|+B>}{\sqrt{3}}+\frac{|-B>}{\sqrt{3}} [/itex]
    where B is some non constant magnetic field.
    How would I figure out what is the probability of the B field being up or down?
    Would it also depend on how the electron interacts with it.
    Maybe we should change our particle to a neutron so the Lorentz force wont dominate.
  2. jcsd
  3. Mar 25, 2013 #2


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    Staff: Mentor

    It is confusing to use the same state description for spin and B-field. I don't know how to get such a superposition, but you can track the evolution of all 4 components (spin up, magnet up, spin up, magnet down, and same for spin down) individually, and add them afterwards.
    Instead of electrons, silver atoms can be used.
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