# Electron in equilibrium

## Homework Statement

A point charge of -1.5 mu or micro CC is located at the origin. A second point charge of 13 mu or micro CC is at x = 1 m, y = 0.5 m. Find the x and y coordinates of the position at which an electron would be in equilibrium.

## The Attempt at a Solution

Force acting on q2

F=k(-1.5e-6C)(13e-6C)/.118^2= -.140 F

Fnet= 0

.140=k(-1.5e-6)(-1.602177e-19)/x^2
x=1.24e-7

tan(x)=.5/1 x=26.56 degrees

sin(z) = y/1.24e-7

y=5.54 e -8

What am I doing wrong?

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gneill
Mentor

## The Attempt at a Solution

Force acting on q2

F=k(-1.5e-6C)(13e-6C)/.118^2= -.140 F
Why? What do you need it for?
By the way, you're missing a "1" in the distance value. It should be 1.118m.

Fnet= 0

.140=k(-1.5e-6)(-1.602177e-19)/x^2
x=1.24e-7

tan(x)=.5/1 x=26.56 degrees

sin(z) = y/1.24e-7

y=5.54 e -8

What am I doing wrong?
Why don't you explain your intended steps? It's not obvious from the calculations you're performing what your thought process is.