# Electron Speed (1 Viewer)

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#### roy5995

Two parallel plates A and B are separated by 5.0cm. The electric potential between the plates is 200V. An electron starts from rest at time t_A and reaches plate B at time t_B. Then the electron goes through an opening and reches point C at time t_C.
What are the speeds at t_A , t_B and t_C?

+ -
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| |
A_B__C
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+ -

#### roy5995

If i use the equation

v=sqr root of [2qV]/m
q=1.602*10^-19
V=200V
m=9.1*10^-31

v=8.4*10^6

I can find velocity. but this means that the velocity will remain the same throughout the whole trip.

Will the electric potential or charge change during the whole trip?
Does the 5cm that the plates are separates affect anything?

#### himanshu121

You are applying the Work Energy Theorem which considers final and initial velocity

Moreover why should e move from + plate to - plate starting from rest all the forces are against the motion

#### roy5995

Originally posted by himanshu121
You are applying the Work Energy Theorem which considers final and initial velocity

Moreover why should e move from + plate to - plate starting from rest all the forces are against the motion
Sorry, you're right, the diagram sould look like this

- +
| |
| |
A_B__C
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- +

#### roy5995

What is the work energy theorem?

What equations can i use to find the initial and final velocities?
Or should i automatically asume that those velocities are zero?(b/c thier potential energies are 0) and that the velocity in the middle (plate B) is 8.4*10^6m/s?

Once the electron passes through the positive plate, would it be attracted back to the plate?

How does the 5.0 cm that the plates are separated affect anything?

#### himanshu121

Work Energy Theorem States that

$$\Delta K = W_{conservative forces}+W_{non conservative forces}$$

$$\Delta K = K_f-K_i$$

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#### himanshu121

With the small distance separating them signifies that the electric field lines are concentrated and are almost parallel to it. Which helps in maintaining uniformity.

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