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Homework Help: Electrons and magnetism.

  1. Feb 25, 2005 #1
    electrons and magnetism. - need help.

    An electron moves with velocity v = (4.0i – 6.0ij) x 104 m/s in a magnetic field B= (-0.80i + 0.60j) T. Determine the magnitude and direction of the force on the electron.

    F=ma: qvB=m*v^2/r : r= mv/qB

    r = (9.1E^-31kg * (4.0i – 6.0ij) x 104 m/s) / (1.6E^-19 C * (-0.80i + 0.60j) T)

    = (3.8E-28i + -5.7E-28j) / (-1.28E-19i + 9.6E-20j)T

    = (-3E-9i - 5.9E-9j)T


    = 9.1E^-31kg (3.8E-28i * -5.7E-28j)2 / (-3E-9i - 5.9E-9j)T

    =(-4.44E-77i + 5.011E-77)T N southward.

    I'm totally stuck on this problem. This is my work but I'm pretty sure it's wrong. I'm not sure how to handle the i, j, k component problems. or is this the way... take the i and j components of the velocity and the magnetic field, and find two separate force components, Fi and Fj. Then assume i and j are perpendicular vectors and then with Fi and Fj find the
    magnitude of the force. Finally, find the angle in the i-j plane in this
    way, knowing that the force would come into the k plane but not at a
    right angle to both i and j?? is that correct?

    thanks, any help would be appreciated.

    Air K
    Last edited: Feb 25, 2005
  2. jcsd
  3. Feb 25, 2005 #2
    I haven't even looked at your work, but the equation for the force of a point charge due to a magnetic field is:

    [tex] \vec{F_B} = q\vec{v} \ X \ \vec{B} [/tex]

    where "X" is the cross product.
    You can calculate F in terms of components i, j, k. (do you know how to do cross product? )

    Then finding the direction and magnitude of F can be done the same way you find the magnitude and direction of any vector.

    The equations you gave are for the radius of an electron in uniform circular motion due to a magnetic field and are completely irrelevant to the question.
    Last edited: Feb 25, 2005
  4. Feb 25, 2005 #3
    hmm, I've done cross product before I'm just not sure if my method is right. I think I posted the same formula as you just did. Will my answer be in terms of I, J, K?

    Don't I need to find "r" to solve the problem?
  5. Feb 25, 2005 #4
  6. Feb 25, 2005 #5
    use this one
    [tex] \vec{F}=q\vec{v}\times\vec{B}[/tex]
    you have v and B already, don't over complicate the problem
    do you know cross product?
  7. Feb 25, 2005 #6
    hmm...why didnt I think of that :tongue2:
    Last edited: Feb 25, 2005
  8. Feb 25, 2005 #7
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