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Electrostatic Force position

  1. Sep 6, 2011 #1
    1. The problem statement, all variables and given/known data

    An electric point charge of Q1 = 5.23 nC is placed at the origin of the real axis. Another point charge of Q2 = 1.89 nC is placed at a position of p = 2.63 m on the real axis. At which position can a third point charge of q = -2.62 nC be placed so that the net electrostatic force on it is zero?

    1.643 m (SOLVED)


    Let the sign of Q2 be changed from positive to negative. At which position can the point charge q be placed now so that the net electrostatic force on it is zero?


    3. The attempt at a solution

    Okay so I set up k(q1)(q2)/d^2=k(q2)(q3)/(D-d)^2 where D = 2.63m

    I then used the quadratic and since there is no b, I used 0.

    I got:
    7.12E-6d^2+0d-3.62E-5 and did the quadratic to get 2.25m but this is not right?

    Help? Thanks!!
     
  2. jcsd
  3. Sep 6, 2011 #2

    Doc Al

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    Staff: Mentor

    The first thing to figure out is which region the charge must be placed: to the left of Q1, between Q1 and Q2, or to the right of Q2. Only one region will give you a sensible answer.
     
  4. Sep 6, 2011 #3
    so the answer should be negative then? Im still having trouble ugh.
     
  5. Sep 8, 2011 #4

    Doc Al

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    Staff: Mentor

    Define d and D more clearly.

    Better still, pick a region and define your distances so they are all positive.
     
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