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Electrostatic self-energy
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[QUOTE="TSny, post: 4535539, member: 229090"] Hello. I don't see where your factor of cos##\theta## comes from in your last equation above. If you're not required to use the equation U = (1/2) [itex]\int[/itex] ρ[itex]\phi[/itex]d[SUP]3[/SUP]r, I think there is an easier way. Imagine bringing in successive thin spherical shells of charge from infinity and building up the charge distribution like layers of an onion. Thus suppose you have currently already built up a spherical distribution of charge of radius r. Find an expression for the change in potential energy dU in bringing in the next layer of charge of thickness dr. Then U = ∫dU. [/QUOTE]
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