Finding Electric Field in Spherical Electrostatics: Vector Specification?

In summary, the problem described is finding the electric field at a point on the z-axis due to a uniformly charged semi-sphere. The difficulty lies in determining the vector from a point on the sphere to the point on the z-axis. Vector addition is used to solve this, resulting in the vector (-a\hat{r} + h\hat{z}). To find its magnitude, the dot product is taken, resulting in |\vec{R}|^2 = h^2 + a^2. However, it is important to remember that \hat{r} is not a simple unit vector, but has spherical components that must be taken into account.
  • #1
Swapnil
459
6
I have a problem in electrostatics in which there is a uniformly charges semi-sphere of radius a with its base in the xy-plane and I want to find the electricfiled at some point h on the z-axis. What I am having trouble with is that how do you specify the vector that goes from an infinitesimal point on the surface of the sphere to the point h on the z axis? Would it be just [tex]h\hat{r} - a\hat{r}[/tex]?
 
Physics news on Phys.org
  • #2
Vector addition. You want the vector that goes from a point on the sphere to a point (0,0,h) on the z axis. Well, that's [itex]-a\hat{r}+h\hat{z}[/itex].
 
  • #3
Is that valid? Can you mix spherical and rectangular coordinates together like that?

Anyways, how would you find its magnitude? Would you just take the squareroot of the dot product? Something like this:

[tex]\vec{R} = h\hat{z} - a\hat{r}[/tex]

[tex]|\vec{R}|^2 = \vec{R}\cdot\vec{R} [/tex]

[tex]= ( h\hat{z} - a\hat{r} )\cdot( h\hat{z} - a\hat{r} ) = h^2\hat{z}\cdot\hat{z} + a^2\hat{r}\cdot\hat{r} = h^2 + a^2[/tex]

Is this correct? Doesn't look right though...
 
  • #4
Remember that [tex] \hat{r} = (a\hat{i} + b\hat{j}+c\hat{k}) [/tex] so you can take the dot product of the z xomponent and the spherical component, where a,b and c are spherical components...look them up in a reference book.
 
Last edited:

1. What is electrostatics in spherical?

Electrostatics in spherical refers to the study of electric charges and their behavior in spherical systems, such as charged spheres or spherical shells.

2. How does electrostatics in spherical differ from electrostatics in other shapes?

Electrostatics in spherical differs from electrostatics in other shapes because of the unique symmetry and geometry of spherical systems. This leads to different equations and solutions for calculating electric fields and potentials.

3. What is the equation for electric field in a spherical system?

The equation for electric field in a spherical system is E = kQ/r^2, where k is the Coulomb's constant, Q is the charge on the sphere, and r is the distance from the center of the sphere.

4. How does the electric field vary inside a charged spherical shell?

The electric field inside a charged spherical shell is zero, regardless of the location within the shell. This is because the charges on the shell cancel out the electric field inside.

5. How is the potential energy calculated in a spherical system?

The potential energy in a spherical system can be calculated using the equation U = kQq/r, where k is the Coulomb's constant, Q and q are the charges on the two objects, and r is the distance between them.

Similar threads

  • Advanced Physics Homework Help
Replies
26
Views
4K
  • Advanced Physics Homework Help
Replies
2
Views
1K
  • Advanced Physics Homework Help
Replies
2
Views
2K
Replies
16
Views
355
Replies
2
Views
722
  • Advanced Physics Homework Help
Replies
4
Views
3K
  • Advanced Physics Homework Help
Replies
7
Views
1K
Replies
19
Views
854
  • Advanced Physics Homework Help
Replies
2
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
2K
Back
Top