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- Thread starter Swapnil
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quasar987

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- #3

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Anyways, how would you find its magnitude? Would you just take the squareroot of the dot product? Something like this:

[tex]\vec{R} = h\hat{z} - a\hat{r}[/tex]

[tex]|\vec{R}|^2 = \vec{R}\cdot\vec{R} [/tex]

[tex]= ( h\hat{z} - a\hat{r} )\cdot( h\hat{z} - a\hat{r} ) = h^2\hat{z}\cdot\hat{z} + a^2\hat{r}\cdot\hat{r} = h^2 + a^2[/tex]

Is this correct? Doesn't look right though...

- #4

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Remember that [tex] \hat{r} = (a\hat{i} + b\hat{j}+c\hat{k}) [/tex] so you can take the dot product of the z xomponent and the spherical component, where a,b and c are spherical components....look them up in a reference book.

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