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**1. The problem statement, all variables and 'given'/'known' data**

A proton accelerates from rest from plate X to plate Y. If the potential difference between the 2 plates is 60.0V, what is the speed of the proton when it reaches plate Y?

**2. Governing equations**

V = E/q

Ekf - 1/2mv^2

## The Attempt at a Solution

E = (60V)(1.6x10^-19C)

E = 9.6x10^-18 V/m

Ekf = 1/2mv^2

9.6E-18 J = 1/2(9.11x10^-31kg)v^2EDIT: added units

And when I solve for v my answer is not correct. So I'm making a mistake somewhere.

Thanks

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