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the following integral confused me a little bit:

[tex] \int_{0}^{\infty} e ^ {-2.x^2} dx [/tex]

The answer is [tex] \sqrt \frac{\pi}{8} [/tex]

and I have no idea where this answer came from. Do I start by saying let

[tex] u = e^ {2x^2} [/tex] ?

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# Homework Help: Elementary functions integral

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