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- Thread starter killerinstinct
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- #2

arildno

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[tex]9+\frac{9}{9}=20_{(base 5)}[/tex]

- #3

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Why shouldnt professors solve what even I can solve? [tex]\frac{(9+9)}{.9}=20[/tex]

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- #4

Zurtex

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lolarildno said:[tex]9+\frac{9}{9}=20_{(base 5)}[/tex]

[tex]9*9 - 9 = 20_{(base 36)}[/tex]

[tex]9*9 + 9 = 20_{(base 45)}[/tex]

[tex]9*(9 + 9) = 20_{(base 81)}[/tex]

[tex]9! + 9 - 9 = 20_{(base 181440)}[/tex]

[tex]9! + 9 + 9 = 20_{(base 181449)}[/tex]

[tex]9^9 - 9 = 20_{(base 193710240)}[/tex]

[tex]9^9 + 9 = 20_{(base 193710249)}[/tex]

etc...

- #5

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Bases are not ELEMENTARY MATH!!!

- #6

arildno

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I think they are elementarykillerinstinct said:Bases are not ELEMENTARY MATH!!!

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ahrkron

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- #8

arildno

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Okay then, I cheated, I'm terribly sorry.

- #9

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killerinstinct said:Bases are not ELEMENTARY MATH!!!

My textbook called Elementary # Theory has bases in it....

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- #11

HallsofIvy

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In any case, why did you say professor's can't solve this? How many professors did you try?

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- #13

arildno

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Do you know about the "four fours" variation of this theme?

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Explain questions? (using four 4s to equal something)?

- #15

arildno

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I'm not absolutely sure about the last member of this set (i.e., 12), it's been a while since I saw it.

(Of course, lots of other numbers can be written using 4 fours too, but they are not consecutive..)

- #16

Njorl

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2 4x4/(4+4)

3 (4+4+4)/4

4 4+(4-4)/4

5 4+(4/4)^4

6 4+(4+4)/4

7 4+4-(4/4)

8 4+4x4/4

9 4+4+4/4

10 (44-4)/4

11 (4!+4)/4+4

12 (4!)x4/(4+4)

I had to use one "44". Is there a way to get 10 without resorting to this?

Njorl

- #17

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arildno said:Okay then, I cheated, I'm terribly sorry.

Very naughty. As punishmnt, you should be whipped with a bundle of rays.

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- #18

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How about [tex]4+4+\frac{4}{\sqrt{4}}[/tex]Njorl said:I had to use one "44". Is there a way to get 10 without resorting to this?

Njorl

- #19

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Last edited by a moderator:

- #20

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Like this:

Code:

```
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
```

For example (I hope I'm not ruining anything for anyone here ):

6 + 6 - 6 = 6

Have fun.

- #21

Njorl

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Grizzlycomet said:How about [tex]4+4+\frac{4}{\sqrt{4}}[/tex]

I think using a square root implicity requires a "2".

- #22

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professors can't solve this? wow.

- #23

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Grizzlycomet said:How about [tex]4+4+\frac{4}{\sqrt{4}}[/tex]

that works for me

- #24

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[(9-sqrt(9))!]/[(sqrt(9)!)^2]

the square root and the square kind of mess it up, but it's still pretty damn sweet

- #25

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Sweet. Good work!

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