Eletrostatics--electric field

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In summary, a spherically symmetric charge distribution with net positive charge Q is distributed within a radius of R. The electric potential V as a function of distance r from the center of the sphere is given by V(r) = (kQ/R)(-2+3(r^2/R^2)) for r<R and V(r) = (kQ/R) for r>R. This can be used to determine the direction and magnitude of the electric field E(r) for different regions. For r<R, the field is radially inward and for r>R, the field is radially outward. This may seem counterintuitive, but it is due to the net positive charge distribution and the given potential function.
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erisedk
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Homework Statement



A spherically symmetric charge distribution has net positive charge Q distributed within a radius of R.
Its electric potential V as a function of the distance r from the center of the sphere is given by the following.
[tex]V(r)=\frac{kQ}{R}( -2+3{\frac{r^2}{R^2}})[/tex]for r<R
[tex]V(r)=\frac{kQ}{R}[/tex] for r>R
https://www.physicsforums.com/file:///page5image8000 https://www.physicsforums.com/file:///page5image8160 https://www.physicsforums.com/file:///page5image9232 Express all algebraic answers in terms of the given quantities and fundamental constants.

  1. (a) For the following regions, indicate the direction of the electric field E(r) and derive an expression for its magnitude.

    i. r < R____ Radially inward ____ Radially outward

    ii. r > R____ Radially inward ____ Radially outward

    The answer to (i), i.e., r<R is radially inward.

Homework Equations

The Attempt at a Solution


How can the field due to a positive charge be radially inward?
For (ii), it's radially outward, which is fairly straightforward, because field lines will originate radially from the sphere, but inside, INWARD??
 
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The problem states that the distribution has a NET positive charge. It doesn't say that it is positive throughout. Look at the given potential function...
 

1. What is an electric field?

An electric field is a physical field that surrounds electrically charged particles, such as electrons or protons. It describes the force that these particles exert on other charged particles within the field.

2. How is an electric field created?

An electric field is created when a charged particle, such as an electron or proton, is present. The charged particle creates an electric field that extends outwards in all directions.

3. What is the unit of measurement for electric field?

The unit of measurement for electric field is Newtons per Coulomb (N/C). This represents the force exerted on a unit charge by the electric field.

4. How does distance affect the strength of an electric field?

The strength of an electric field is inversely proportional to the square of the distance from the source of the field. This means that as the distance increases, the strength of the field decreases.

5. Can an electric field exist without a charged particle?

No, an electric field cannot exist without a charged particle. The presence of a charged particle is necessary to create an electric field.

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