Two balls, of masses mA = 40 g and mB = 72 g are suspended as shown in Figure 7-44. The lighter ball is pulled away to a 60° angle with the vertical and released. (a) What is the velocity of the lighter ball before impact? (Take the right to be positive.) (b) What is the velocity of each ball after the elastic collision? ball A ball B (c) What will be the maximum height of each ball (above the collision point) after the elastic collision? ball A ball B Ok so i found part A by doing Square root of 2*9.8*.15 and got 1.71 which is correct. Part B i got -.488 for the velocity of A and it is correct Part B i got 1.22 for the velocity of B and it is correct Where i am lost is how to find the heights of each. I tried doing (.488^2)/ 2 *9.8*sin 60 and i get .01402 m It is incorrect any help?