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Ellipse in standard form

  1. Mar 23, 2010 #1
    1. The problem statement, all variables and given/known data
    Graph the following:
    [tex]15(x+2)^2 + \frac{(y+3)^2}{4} = 4[/tex]

    2. Relevant equations

    3. The attempt at a solution

    I can't seem to get both coefficients to 1, since the right side is only 4. If I multiply the whole thing by 4, I can get rid of the denominator on the y term, but then the coefficient of the x jumps to 60, and 60 won't reduce the coefficient to 1. So I'm stuck. Can anyone help? This is not homework, just a practice question that's bugging me...
  2. jcsd
  3. Mar 23, 2010 #2

    Filip Larsen

    User Avatar
    Gold Member

    You want to divide both sides by 4 so that you get a 1 on right hand side. Now you only need to collect the denominators into the form a2 and b2 and identify what h and k is. If you have trouble with the 15 then notice that multiplying something with 15 is the same as dividing by 1/15.
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