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If a particle's trajectory is defined by the law x=acos[pt] and y=bsin[pt] where t is parameter of time then we have to prove that it's acceleration vector passes through the focus of the conic----ellipse in this case as can be clearly seen.
If we write out the position vector in the vector notation and differentiate twice we get a=-p^{2}r and this clearly is directed towards the centre of the axes system and not the focus.Any ideas?
If we write out the position vector in the vector notation and differentiate twice we get a=-p^{2}r and this clearly is directed towards the centre of the axes system and not the focus.Any ideas?