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An elevator starts from rest with a constant upward acceleration and moves 1 m in teh first 1.5s. A passenger in the elevator is holding a 9.8 kg is holding a 9.8 kg bundle at the end of a vertical cord. G=9.8 m/s^2. What is the tension in the cord as teh elevator accelerates? Answers in units of N.

my work: (9.8kg * g)((4/9 m/s^2)/g + 1) = 96.04(1.045351474)=100.39555556 the 4/9 is the acceleration in the y direction 1/1.5/1.5 so m/s^2 right? this wasnt right what is wrong?

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# Homework Help: Elvator tension problem

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