Calculating Rate of Change of Electric Field in a Circular Capacitor

In summary, we discussed a circular parallel plate capacitor with plates of radius 0.1m and a separation distance of 0.10 mm. A current was supplied to charge the capacitor, causing a potential difference increase of 10 V/μs. The magnitude of the rate of change of the electric field between the plates is 1 x 10^11 V/m. The equation for electric field in terms of voltage and distance is dV/dt = Ed, and using this equation, we were able to solve for the rate of change of the electric field. It is important to watch units and exponents when solving these types of problems.
  • #1
dekoi
A circular parallel plate capacitor has plates of radius 0.1m; the plates are separated by 0.10 mm. A current is supplied to charge the capacitor. While charging, the potential difference across the capacitor increases by 10 V/μs.

What is the magnitude of the rate of change of the electric field between the capacitor plates? Answer= 1 x 10^11 V/m.

What exactly is the "rate of change of the electric field"? dE/dt? dΦ/dt? Φ?
I have tried different methods using all three of those and have yet to receive the correct answer.

I am using: ⌡E.dA = Q/ε for dE/dt
and Φ= Q/ε for dΦ/dt and Φ
 
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  • #2
I get the correct answer. What is the equation for electric field, in terms of voltage and distance? You are given dV/dt, and the separation distance...

Just watch your units and exponents.
 
  • #3
Wow! Thanks for the quick reply, I'm in urgent need right now.


Thank you for the information, as it helped me get the right answer.
 

1. What is an EM capacitor?

An EM capacitor is a device that stores electrical energy in the form of an electric field. It consists of two conductive plates separated by an insulating material, also known as a dielectric. When a voltage is applied to the plates, one plate becomes positively charged and the other becomes negatively charged, creating an electric field between them.

2. How does an EM capacitor work?

An EM capacitor works by utilizing the electric field created between its two conductive plates. When a voltage is applied to the capacitor, one plate becomes positively charged and the other becomes negatively charged. The insulating material between the plates, also known as a dielectric, prevents the charges from flowing together and therefore stores the energy in the form of an electric field.

3. What are the applications of EM capacitors?

EM capacitors have a wide range of applications in various electronic devices. They are commonly used in power supplies to filter out unwanted signals and provide smooth DC power. They are also used in audio equipment to block DC signals and allow only AC signals to pass through. Other applications include energy storage, timing circuits, and signal coupling in electronic circuits.

4. How are EM capacitors different from other types of capacitors?

EM capacitors differ from other types of capacitors in terms of their construction and materials used. They have a higher capacitance per unit volume compared to other types of capacitors, making them suitable for high energy storage applications. They also have a higher breakdown voltage, allowing them to withstand higher voltages. Additionally, EM capacitors have low self-inductance and resistance, making them ideal for applications that require fast charging and discharging.

5. Can EM capacitors be used in high-frequency applications?

Yes, EM capacitors can be used in high-frequency applications. In fact, they are often preferred over other types of capacitors in high-frequency circuits due to their low self-inductance and resistance. However, it is important to choose the right type of EM capacitor for the specific frequency range required in the application, as different types of dielectric materials have different frequency responses.

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