Exploring Wave Behaviour of EM Waves Based on Oscillation Patterns

In summary: As you can see, the waveforms emitted at different angles are not sinusoidal, but instead are distorted versions of the original sinusoid.So, what this means is that when you analyse an atomic spectrum, you're not only looking at a continuous spectrum of energy, but you're also looking at a spectrum of waveforms which have been distorted by the oscillator. This is why the spectra of elements are discrete - the individual waves emitted by the atoms have been distorted by the oscillator.
  • #1
Hydr0matic
197
1
I have an idea that I've tried to express on this forum before but without success. There's a lot of reasoning behind the idea so it won't do no good just blurting it out. I want to lead you and see if you reach the same conclusion... So here goes...

First question... In classical physics, how would the behaviour of the electromagnetic wave emitted by a charge differ depending on http://hydr0matic.insector.se/fysik/oscillationpatterns.jpg [Broken] ?

As you can see, all oscillation patterns have the same frequency, which would give all three emitted EM waves the same wavelength, correct ?

Now, if all waves would have the same wavelength, would they differ in some other way perhaps ? Because they're emitted by charges oscillating in different ways, one (I) would expect them to.
 
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  • #2
Somethin' wrong with my question ? :smile: Anyone understand it ?

Never mind _how_ they would differ, just answer the question _if_ they would differ..
 
  • #3
I'm guessing that the different waveforms would interfere with each other in different ways.
 
  • #4
ok, thnx :smile:. I agree...

Next question...

Let's say an oscillator is traveling back and forth, a relatively long distance, in your direction. This would cause a basic doppler effect on the EM waves you see. Now, if instead of traveling b&f, the oscillator was not only oscillating vertically, but also horisontally (in your direction), would this still be considered dopplereffect ?

If you were to hold a prism in front of you, would the horisontal oscillation result in you "seeing" more than one beam ? Even if one half of the period was blueshifted and the other one redshifted ?
 
  • #5
Well, (I not sure I know what I'm talking about here ... ;) )

But, you didn't specify what would happen to the magnetic component waveform. Stay the same, or be a mirror image of the electric component?

I would expect some kind of "disruption" between the electic and magnetic component, especially in the second waveform as the electric component would be expressed more.
 
  • #6
Originally posted by Nacho
Well, (I not sure I know what I'm talking about here ... ;) )

But, you didn't specify what would happen to the magnetic component waveform. Stay the same, or be a mirror image of the electric component?

I would expect some kind of "disruption" between the electic and magnetic component, especially in the second waveform as the electric component would be expressed more.
Don't let the patterns fool you :smile:. If the field potential isn't symmetric, the oscillation won't be either. But in either case the EM waves' E vector is always proportional to its B vector.
 
  • #7
The waveforms which are not perfect sin waves (the last 2) can be represented as a Fourier sum of sine waves. The energy distribution will show contributions at higher frequencies thus the transmitted waves will be a superposition of these waves.

What is your question by the way?
 
  • #8
Originally posted by Integral
What is your question by the way?
What I'm asking is if an EM wave, emitted by a charge oscillating vertically and horisontally, could produce multiple discrete lines when passed through a prism.
 
  • #9
Originally posted by Hydr0matic
What I'm asking is if an EM wave, emitted by a charge oscillating vertically and horisontally, could produce multiple discrete lines when passed through a prism.

A sinusoidal oscillation will produce a "pure" wave of one frequency, so that only one spectral line will be produced. Any other type of oscillation will produce harmonics so that a discrete spectrum will be produced.

That is an exact answer, by the way.
 
  • #10
Originally posted by Tyger
Any other type of oscillation will produce harmonics so that a discrete spectrum will be produced.
Ok, thnx Tyger.

If this was the understanding of 19th century physicists, why were they so puzzled by the discreteness in atomic spectra ?

Ok, enough questions... I'll just spit it out...

There are two things I need to discuss for you to understand my idea - waveforms produced by an oscillator, and the principle of reinforcement.


When you perform spectroscopy on an element there are not one, but billions of oscillators, all vibrating in random directions. So when analysing the spectrum emitted one needs to consider all waveforms 360° around the oscillator. With the basic sinusodial oscillator, you'll get a continuous spectrum of waveforms stretching from it's non-dopplereffected waveform, emitted perpendicular to the direction of oscillation, to it's most dopplereffected waveform, emitted in the direction of oscillation. How wide this spectrum will be is dependent on the amount of dopplereffect, which in turn is dependent on the speed of the oscillator (i.e. the temperature).

I've tried to illustrate this with http://hydr0matic.insector.se/fysik/oscillationpatterns2.gif [Broken] ...

In pic 1 I want to show that a sinusodially oscillating charge will produce a non-sinusodial waveform at every angle except perpendicular to the oscillation. When viewed from coordinate X2, the oscillation will be split into a vertical movement and a horisontal one (which produces the dopplereffect), unlike the X1 coordinate, where there's only a vertical oscillation with no doppler.

In pic 2 I've used a snapshot from a flashmovie to illustrate the different waveforms around the charge ...

[ !OBS! Due to the alignment of the waves there is an alternate view with "depth" in pic 2. This is not intended. The image is meant to be a 2D cross-section. ]

http://hydr0matic.insector.se/fysik/spectrum.gif [Broken] illustrating the connection between temperature and spectrum. Let me know if I haven't explained this well enough ...


The next thing we have to discuss is the principle of reinforcement. I don't think this is the official name for it though ...

Getting a wave to higher amplitudes require that you add energy to it in sync with it, i.e. you "reinforce it" in phase. This is pretty basic wave theory so I'll just leave it at that. How this relates to my spectrum of waveforms is very simple. As I said earlier, every waveform except the perpendicular one will be dopplereffected. So instead of a single pure sinuswave, each wave will have one half of it's period blueshifted and the other half redshifted. Although this dopplershift affects the outcome in a prism, it does not affect the overall frequency, no matter which direction the charge is oscillating. This means that, if a blue- or redshifted part of the wave has a wavelength that doesn't match the overall frequency, the receiving oscillator will not be reinforced ! And this my friends, is the key to understanding the hydrogen spectrum classically...

Since all redshifted parts have wavelengths longer than that of the overall frequency, none of them will be reinforced efficiently.

Mathematically speaking, only blueshifted parts with a wavelength α that is an integer fraction of the overall wavelength λ will be reinforced. So the wavelengths we will see in our "spectrum of waveforms", will be those where α = λ / n ( n=1,2,3...).


So... there it is... ... What do you think ? Anything I need to elaborate ?
 
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  • #11
I forgot.. there's a catch. The idea only works if the spectrum is temperature dependent. And according to current theory, it's not.

If I'm not mistaken though, each of the hydrogen series (Lyman, Balmer, etc) are produced at different temperatures, which works to my favor. But I don't consider it very likely that 20th century physicist could have missed the fact that the lines moved when the temperature changed...

.. but who knows ?
 

1. What are electromagnetic waves?

Electromagnetic waves are a form of energy that can travel through space and matter. They consist of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of wave propagation.

2. How do electromagnetic waves behave?

Electromagnetic waves behave like transverse waves, which means that the oscillations of the electric and magnetic fields are perpendicular to the direction of wave propagation. They also exhibit properties of reflection, refraction, diffraction, and interference.

3. What is meant by oscillation patterns in EM waves?

Oscillation patterns in EM waves refer to the repeating cycles of the electric and magnetic fields as they propagate through space. These patterns can be described by the frequency, wavelength, and amplitude of the wave.

4. How can we explore the wave behaviour of EM waves?

The wave behaviour of EM waves can be explored through experiments and observations. This can involve studying the reflection, refraction, diffraction, and interference of EM waves, as well as measuring their frequency, wavelength, and amplitude.

5. What are some real-world applications of understanding EM wave behaviour?

Understanding the behaviour of EM waves is crucial in many fields, such as telecommunications, astronomy, and medical imaging. It allows us to transmit and receive information through radio waves, study the properties of distant galaxies, and create images of the human body using techniques like X-rays and MRI scans.

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