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Embed Sn in A(n+2)

  1. May 3, 2009 #1
    How would you embed the symmetric group on n letters in the alternating group of (n+2) letters??? I'm actually trying to write down an explicit map but can't seem to come up with one. I know An will be a subgroup of A(n+2) but I have a feeling that a map that is the identity on An and not-the-identity elsewhere won't work. Any thoughts?
     
  2. jcsd
  3. May 3, 2009 #2
    Imagine a set U of n+2 symbols. A permutation p in Sn acts on the first n of these. If p is an odd permutation, define a new permutation f(p) on U by f(p) = p * t, where t is the extra transposition (n+1, n+2). Clearly, f(p) is in An+2. If p is an even permutation, define f(p) = p. It's easy to show that f is a homomorphism with trivial kernel.
     
  4. May 3, 2009 #3
    Thanks!
     
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