Suppose that a man driving a BMW zooms out of a darkened tunnel at 39.2 m/s. He is momentarily blinded by the sunshine. When he recovers, he sees that he is fast overtaking a camper ahead in his lane moving at the slower speed of 15.7 m/s. He hits the brakes as fast as he can (his reaction time is 0.26 s). If he can decelerate at 3.5 m/s2, what is the minimum distance between the driver and the camper when he first sees it so that they do not collide?
The Attempt at a Solution
I took the second equation and plugged in the numbers [V=39.2(0.26)+1/2(3.5)(0.26^2)] and ended with the answer being 10.3103. When I put my answer in, it was wrong. Please help me!!