# EMF and induced current question

1. Dec 3, 2008

### StephenDoty

The rectangular loop in the figure has 1.7×10^−2 ohm resistance. What is the induced at this instant? See picture below. Answer is in terms of I, like 5*I.

emf = Bvl
I= emf/R

B= [$$\mu$$_0 / 2*pi] *I * ln(.03/.02) since the magnetic field goes through the loop from 2cm to 3cm

then I used this magnitude in emf=B*10*.04 and then used the emf to find the induced current:

I = emf/ (1.7*10^-2)

However, the answer I got using these calculations was incorrect. What did I do wrong?

Thanks.
Stephen

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