EMF find the electric field

  • #1
132
3

Homework Statement


upload_2017-2-24_11-8-43.png

The region is a circle with radius=a

Homework Equations


upload_2017-2-24_11-8-58.png

Using Faraday's law to find E.

The Attempt at a Solution


Dealing with the Left side of the second equation first
1.) Pull out the Partial/partial t because it is a constant in this equation
2.) Now I have B dot (n-hat) da
3.) Using the dot product I know that I have |B||da|cos(theta)
4.) the angle between them is zero so I have B*da
5.) I can pull B out and integrate over the area of the circle which gives me A=2(pi)(r)^2 =2(pi)(a)^2
6.) Now I have
-[2(pi)(a)^2 * Partial(B)/partial t] this is also equal to equation 1 our emf induced
7.) Taking the partial of B with respect to t gives me
-[2(pi)(a)^2 *
upload_2017-2-24_11-21-14.png
]

Now I deal with the right side of equation 2 which is equal to 7.)

[/B]
8.) I know that E is parallel to dl and that I can pull E out
9.) Now I integrate over dl which just gives me

E*2(pi)(r)= -[2(pi)(a)^2 *
upload_2017-2-24_11-21-14.png
]

of course excluding the B(x,y,t).

Then I divide by 2(pi)r)
Which will give me E if I did everything correctly

 

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Answers and Replies

  • #2
kuruman
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5.) I can pull B out and integrate over the area of the circle ...
Is B constant over the surface area of the circle?
 
  • #4
kuruman
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Yes
I think not. The question says ##\vec{B}(x,y,t) = B_0 \cos (\pi x/L) \cos(\pi y /L) \sin (\omega t) \hat{k}##. At different values of x and y inside the circle the field has different values.
 
  • #5
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Well we don't usually do anything that's not constant because it would make it complicated. We always deal with constant things. So my assumption since it was not stated was that B was constant
 

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