in acid medium the standard reduction potential of NO converted to N2O is 1.59V .its standard potential in alkaline meduim at 298k would be?
a)2NO+2H ---> N2O +H20 E=1.59
b)2NO + H2O ---->N2O + 2OH- E=x
c)2H2O---->2H+ + 2OH- E=0.826 (calculated, correct and verified)
The Attempt at a Solution
Reversing b) we get E= -x
adding a and reversed b, we get reversed c. Therefore 1.59-x=-0.826, so x should be 1.59+0.826 but this is incorrect. Where am I wrong? any help would be appreciated.