- #1
atavistic
- 106
- 0
When we say heat released in a circuit is i^2 RT , who/what is the cause of this energy loss; is it the battery mechanism? Since work done on charge in the circuit by E field is zero, the only other force seems to be the battery mechanism, right? But in textbooks there is so much implication that the resistor is the root cause of heat, I am confused.