Emission of photo by electron

  • Thread starter NATSALANE
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an electron travels at 1 x 106 m/s. when it hits a target, its speed decrease in half and a photo is released. find the phton's wavelength.

so far i know E photon = (hc) / lamda

what about the speed? does the photons' energy same as kinetic energy of the electron which is just 1/2 mv ^2? if so, do i use the halved speed or the initial?
 

Answers and Replies

  • #2
nicksauce
Science Advisor
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Apply conservation of energy:

E_electron_inital = E_electron_final + E_phton
 

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