Emissivity of a flat surface varies with zenith angle

  • Thread starter Callisto
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  • #1
Callisto
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If the emissivity of a flat surface varies with zenith angle according to

e=E*cos(theta)
where E is the emissivity at zenith.
Would this surface radiate isotropically?

I think that because the emissivity varies then the emitted radiation varies accordingly so the energy measured from any fixed point and at any angle would not be the same so therefore the surface would be an anisotropic source of radiation.

Does this sound like a fair argument?
anybody care to correct me?

Callisto
 

Answers and Replies

  • #2
Antiphon
1,683
3
Callisto said:
If the emissivity of a flat surface varies with zenith angle according to

e=E*cos(theta)
where E is the emissivity at zenith.
Would this surface radiate isotropically?

I think that because the emissivity varies then the emitted radiation varies accordingly so the energy measured from any fixed point and at any angle would not be the same so therefore the surface would be an anisotropic source of radiation.

Does this sound like a fair argument?
anybody care to correct me?

Callisto


No, the surface is an isotropic radiator. The cos law means the projected
area of the surface is being reduced. Any deviation from the cos variation
means it's not an isotropic radiator.
 

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