- #1
matematikuvol
- 192
- 0
If we watch some translation in space.
[tex]L(q_i+\delta q_i,\dot{q}_i,t)=L(q_i,\dot{q}_i,t)+\frac{\partial L}{\partial q_i}\delta q_i+...[/tex]
and we say then
[tex]\frac{\partial L}{\partial q_i}=0[/tex]
But we know that lagrangians [tex]L[/tex] and [tex]L'=L+\frac{df}{dt}[/tex] are equivalent. How we know that [tex]\frac{\partial L}{\partial q_i}\delta q_i[/tex] isn't time derivative of some function [tex]f[/tex]?
[tex]L(q_i+\delta q_i,\dot{q}_i,t)=L(q_i,\dot{q}_i,t)+\frac{\partial L}{\partial q_i}\delta q_i+...[/tex]
and we say then
[tex]\frac{\partial L}{\partial q_i}=0[/tex]
But we know that lagrangians [tex]L[/tex] and [tex]L'=L+\frac{df}{dt}[/tex] are equivalent. How we know that [tex]\frac{\partial L}{\partial q_i}\delta q_i[/tex] isn't time derivative of some function [tex]f[/tex]?