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Endothermic reaction, find heat.

  1. Mar 10, 2013 #1
    1. The problem statement, all variables and given/known data
    given:

    2 H3PO4 + 3 Mg(OH)2 + 1427 kj → 6 H20 + Mg3(PO4)2

    How much heat is involved if 927 grams of Mg(OH)2 reacts?


    2. Relevant equations



    3. The attempt at a solution

    927 g x Mg(OH)2 mole/56.305g x 1427 kj/3Mg(OH)2 mole = 70,482 kj


    I just felt like I did this wrong. Also how do I make the numbers small for showing the number of each element?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Mar 11, 2013 #2

    Borek

    User Avatar

    Staff: Mentor

    No idea where 1427 kj/3Mg(OH)2 mole came from - you have not listed it in the problem. It doesn't have to be wrong, it is just not clear if it is OK.

    [noparse]H3O+[/noparse] renders as H3O+.
     
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