Energies in the LHC

  • #1
748
40
Due to the blogs being removed, I thought it might be worthwhile posting a few in the forums-


The Large Hadron Collider has produced collisions at 7 TeV. For collisions at 7 TeV, protons need to be ‘ramped’ to 3.5 TeV, the proton has a mass of 1.6726e−27 kg which, according to mass–energy equivalence (E=mc2), is 938.272 MeV where 1 eV= 1.6022e−19 Joules. The proton will be accelerated to 0.999999964c (11,103.4 revolutions of the LHC per second) which means the following relativistic equation can be used-

ET= γmc2

where ET is energy total and γ=1/√(1-(v2/c2)). γ is the Lorentz factor and tells us how much the energy of an object increases due to kinetic energy.

which produces a total of ET=3.4967 TeV

This is also supported by Einstein’s more complete mass-energy equation-

ET=√(m2c4+p2c2)

where p is momentum and is expressed p=γmv (or p=h/λ in the case of light where h is Planck’s constant and λ is wavelength).

which produces a total of ET=3.4959 TeV

CERN hope to conduct collisions at 14 TeV which would require speeds of up to 0.999999991c (1-8.98e−9c)

Another interesting aspect is the effect on time for the proton. The relativistic equation for time dilation is-

τ=t/γ

where τ is proper time relative to the proton and t is coordinate time, or time according to a (relatively) static frame. In this case, at energys of 3.5 Tev, the time dilation for the proton is 2.6833e−4 which means for every hour that passes outside the accelerator, only 1 second passes for the proton (0.966 seconds), at 7 TeV, only ½ a second would pass (0.483 seconds). The application of the Lorentz factor to time dilation can be supported by looking at a basic spacetime metric derived from Minkowski space time, accordingly-

c22=c2dt2-dx2

again, where τ is the proper time of the moving object, t is coordinate time and x is the distance covered. x can be rewritten as-

dx2=v2dt2

where v=dx/dt (i.e. velocity is m/s), v2=dx2/dt2 which can be rewritten as above. The spacetime metric can now be written as-

c22=c2dt2-v2dt2

2=(c2dt2-v2dt2)/c2

dτ=√((c2dt2-v2dt2)/c2)

=√(dt2(1-v2/c2))

= dt√(1-v2/c2)

which is equivalent to τ=t/γ.

Time dilation for relativistic sub-atomic particles is also supported by muons (high energy leptons) which enter the atmosphere from space, according to our clocks, the muon should decay at 660 m into the atmosphere based on a life span of 2.2e−6 seconds and a velocity of 0.9996678c but due to time dilation (τ=0.02577), muons survive the flight to earth's surface and can penetrate tens of meters of rock before decaying.
 
Last edited:

Answers and Replies

Related Threads on Energies in the LHC

  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
6
Views
2K
Replies
38
Views
4K
  • Last Post
Replies
13
Views
4K
Replies
21
Views
3K
  • Last Post
Replies
11
Views
3K
  • Last Post
Replies
7
Views
3K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
16
Views
5K
Top