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Physics
Classical Physics
Mechanics
Energy change of reservoir in reversible weight process
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[QUOTE="Sebi123, post: 5567899, member: 603115"] Maybe I should rephrase the problem above. The short version is: In a reversible weight process, in which system A goes from state A[SUB]1[/SUB] to A[SUB]2[/SUB] and reservoir R from R[SUB]1[/SUB] to R[SUB]2[/SUB], the energy transferred to the weight is (W[SUB]12[/SUB][SUP]AR→[/SUP])[SUB]rev[/SUB] = E[SUB]1[/SUB] - E[SUB]2[/SUB] + E[SUB]1[/SUB][SUP]R[/SUP] - E[SUB]2[/SUB][SUP]R[/SUP] = Ω[SUB]1[/SUB][SUP]R[/SUP] - Ω[SUB]2[/SUB][SUP]R[/SUP] This is equation 6.5 in section 6.6.4. On the other hand, in section 6.6 the authors say: "[A] weight process for system A from A[SUB]1[/SUB] to A[SUB]2[/SUB] is [...] reversible only if" Ω[SUB]1[/SUB][SUP]R[/SUP] - Ω[SUB]2[/SUB][SUP]R[/SUP] = E[SUB]1[/SUB] - E[SUB]2[/SUB] (eqn. 6.7) This would mean that the reservoir does not exchange energy, as E[SUB]1[/SUB][SUP]R[/SUP] - E[SUB]2[/SUB][SUP]R[/SUP]. However, in example 6.4 they get E[SUB]1[/SUB][SUP]R[/SUP] - E[SUB]2[/SUB][SUP]R[/SUP] = -50 kJ ≠ 0. Why do both equations contradict? [/QUOTE]
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Mechanics
Energy change of reservoir in reversible weight process
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