# Energy Dissipation in a Wire

#### haroharo

1. The problem statement, all variables and given/known data

Two 10-cm-diameter metal plates are 1.0 cm apart. They are charged to +/-12.5 nC. They are suddenly connected together by a 0.224-mm-diameter copper wire stretched taut from the center of one plate to the center of the other.

d)What is the total amount of energy dissipated in the wire?

2. Relevant equations
What is the maximum current in the wire?
4.17*105 A

What is the largest electric field in the wire?
1.80*105 V/m

U=qV

3. The attempt at a solution
I figure that you can't find the energy density and find the volume the wire occupies in the capacitor because the wire has a certain resistance restricting the flow, thus affecting the potential energy.

Attempt1:
U=qV where q = 1.6*10-19 or 12.5*10-9 & V =1.8*103
=2.88*10-16 or 2.25*10-5

Attempt 2:
=(.5)(0.0001122*pi)(0.01)(1.80*105)2*(8.854*10-12)
=5.64*10-11J

Helps Appreciated!

#### Delphi51

Homework Helper
Well, it seems to me that all the energy in the capacitor will be dissipated.
Have you got a formula for the energy of a capacitor (with charge in it)?

#### haroharo

actually i do
awesome, thanks for the clarification!

#### leggomaeggo

1. The problem statement, all variables and given/known data

Two 10-cm-diameter metal plates are 1.0 cm apart. They are charged to +/-12.5 nC. They are suddenly connected together by a 0.224-mm-diameter copper wire stretched taut from the center of one plate to the center of the other.

d)What is the total amount of energy dissipated in the wire?

2. Relevant equations
What is the maximum current in the wire?
4.17*105 A

What is the largest electric field in the wire?
1.80*105 V/m

U=qV

3. The attempt at a solution
I figure that you can't find the energy density and find the volume the wire occupies in the capacitor because the wire has a certain resistance restricting the flow, thus affecting the potential energy.

Attempt1:
U=qV where q = 1.6*10-19 or 12.5*10-9 & V =1.8*103
=2.88*10-16 or 2.25*10-5

Attempt 2:
=(.5)(0.0001122*pi)(0.01)(1.80*105)2*(8.854*10-12)
=5.64*10-11J

Helps Appreciated!

Hey how'd u get the max current and the largest electric field in the wire?
Help would be much appreciated.Thanks in advance :)

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