- #1
ant284
Hi
I have the following question
4Hydrogen->Helium+2electrons+2neutrino+gamma
In the sun, Hydrogen is converted into helium(see equation above) and that the reaction releases about 26.7MeV of energy. the sun radiates energy at the rate of 3.9*10^26W and has a mass about 1.99*10^30 kg of which 75% is hydrogen. Find out how long it will take the sun to convert 12% of its hydrogen into helium.
I'm abit blocked. anyhelp is appreciated
I think i have the right ideas.
For Four hydrogen into helium is 26.7Mev or 4.272*10^-12Joules.
now a hydrogen is about 1.008 or 1.0u or 1* (1.66*10^-27)kg.
so I do, (1.99*10^30) *.75=1.425*10^30kg and
i do answer * .12 to get those 12% of hydrogen to helium
1.42*10^30 * .12 = 1.79*10^29kg.
so i can do (1.79*10^29)/(1.66*10^-27) to get the number of Hydrogen
so i get 1.08*10^56 hydrogen.
since 4 Hydrogen into helium i divide by the total number of hydrogen to get
(1.08*10^56)/4=2.7*10^55
i multiply 2.7*10^55 by 26.7MeV to get the total energy output.
so i get
(2.7*10^55)*(4.272*10^-12)=1.15344*10^44
and since
watts=J/S, so i do 1/(3.9*10^26) * (1.15344*10^44) and i get
2.96*10^17 seconds.
I could get it into years by dividing the answer by (60*60*24*365) and i get about
9.4*10^9 years.
Any help is appreciated.
I have the following question
4Hydrogen->Helium+2electrons+2neutrino+gamma
In the sun, Hydrogen is converted into helium(see equation above) and that the reaction releases about 26.7MeV of energy. the sun radiates energy at the rate of 3.9*10^26W and has a mass about 1.99*10^30 kg of which 75% is hydrogen. Find out how long it will take the sun to convert 12% of its hydrogen into helium.
I'm abit blocked. anyhelp is appreciated
I think i have the right ideas.
For Four hydrogen into helium is 26.7Mev or 4.272*10^-12Joules.
now a hydrogen is about 1.008 or 1.0u or 1* (1.66*10^-27)kg.
so I do, (1.99*10^30) *.75=1.425*10^30kg and
i do answer * .12 to get those 12% of hydrogen to helium
1.42*10^30 * .12 = 1.79*10^29kg.
so i can do (1.79*10^29)/(1.66*10^-27) to get the number of Hydrogen
so i get 1.08*10^56 hydrogen.
since 4 Hydrogen into helium i divide by the total number of hydrogen to get
(1.08*10^56)/4=2.7*10^55
i multiply 2.7*10^55 by 26.7MeV to get the total energy output.
so i get
(2.7*10^55)*(4.272*10^-12)=1.15344*10^44
and since
watts=J/S, so i do 1/(3.9*10^26) * (1.15344*10^44) and i get
2.96*10^17 seconds.
I could get it into years by dividing the answer by (60*60*24*365) and i get about
9.4*10^9 years.
Any help is appreciated.