Energy equation diffusion

  • Thread starter lesy1
  • Start date
  • #1
12
0
Imagine a wall (membrane). Concentration of a specimen A on one side of the wall is cA and it has the temperature TA. The concentration of a specimen B on another side of the wall is cB and it has the temperature TB. Specimen A nad B diffuse against each other (assume steady state). Can somebody write the energy balance equation for this case?
 

Answers and Replies

  • #2
12
0
The specimen A diffuses from the side of the membrane with the concentration cA (side 1) to the other side (side 2) and specimen B diffuses in the opposite direction. Because the temperature at the side 1 is TA and the temperature at the side 2 is TB is heat flux in both directions:
mA*(hA(TA)-hA(TB))
mB*(hB(TB)-hB(TA))

mA, mB - diffusion flux of specimen A/B
hA(TA) - specific enthalpy of specimen A at TA
hA(TB) - specific enthalpy of specimen B at TB
 
  • #3
12
0
Is that correct?
 

Related Threads on Energy equation diffusion

  • Last Post
Replies
0
Views
1K
Replies
18
Views
3K
Replies
1
Views
2K
Replies
1
Views
8K
Replies
2
Views
831
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
5
Views
4K
  • Last Post
Replies
2
Views
785
Replies
3
Views
2K
  • Last Post
2
Replies
29
Views
2K
Top